(5x^2-10)=(4x^2-3x)

Solution for (5x^2-10)=(4x^2-3x) equation:

(5x^2-10)=(4x^2-3x)

We move all terms to the left:

(5x^2-10)-((4x^2-3x))=0

We get rid of parentheses

5x^2-((4x^2-3x))-10=0


We calculate terms in parentheses: -((4x^2-3x)), so:

(4x^2-3x)

We get rid of parentheses

4x^2-3x

Back to the equation:

-(4x^2-3x)


We get rid of parentheses

5x^2-4x^2+3x-10=0

We add all the numbers together, and all the variables

x^2+3x-10=0

a = 1; b = 3; c = -10;
Δ = b2-4ac
Δ = 32-4·1·(-10)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-7}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+7}{2*1}=\frac{4}{2}
=2
$